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  • 半導(dǎo)體類筆試題目

    時間:2020-12-07 20:14:15 筆試題目 我要投稿

    半導(dǎo)體類筆試題目

    A Test for The C Programming Language
      I. History
    1. C was originally designed for and implemented on the (what) operating system on the DEC PDP-11, by (who) .
    2. The most recently approved ANSI/ISO C standard was issued in (when), and single line comments notation “//” is or isn’t a feature of C89.
      II. Syntax and Semantics 1.In a runtime C program, auto variables are stored in , staticvariables are stored in , and function parameters are stored in .
      a. stack b. heap c. neither stack nor heap
    2. The statement “extern int x;” is a , and the keyword extern is used during .
      a. variable declaration b. variable definition c. compilation time d. runtime
    3. There is a complicated declaration: void ( * signal (int, void(*)(int)) ) (int);If a statement “typedef void (*p) (int);” is given,please rewrite this complicated declaration.
    4. The following code is a segment of C program.
      ..........
      void func(int *p)
      {...........}
      ..........
      main()
      {
      int num=0;
      .........
      func(&nu(文章轉(zhuǎn)載自[個人簡歷網(wǎng)] http://www.gerenjianli.com 請保留此標(biāo)記)m);
      ........
      }
      ..........
    Here, the function argument “&num” is passed .
     a. by value b. by reference
      III. Practice
      Create a tree, which has h (h>0) layers, and its each node has w(w>0) sub-nodes.Please complete the following incomplete solution.
      #include <stdlib.h>
      #include <string.h>
      struct tree{
      char info;
      p_sub; //link to sub-nodes};
      // allocate memory and initiate
      void dnode ( struct tree* tmp )
      {
      = malloc( sizeof (struct tree) );
      = 0x41;
      = NULL;
      }
      struct tree *dtree (struct tree* subtree, int height, int width)
      {
      int i;
      if ( !subtree ) //if necessary, allocte memory for subtree
      denode(subtree);
      if ( height == 1 )
      return subtree;
      else if ( height == 2 ) {
      struct tree *leaf = NULL;
      for ( i=0; i<width; i++ ) {
      denode ( );
      ;
      leaf = NULL;}
      return subtree;}
      else {
      for ( i=0; i<width; i++ ) {
      }
      return subtree;
      }
      }
      main()
      {
      .........
      struct tree *root = NULL;

    半導(dǎo)體類筆試題目

     

     

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