<dfn id="w48us"></dfn><ul id="w48us"></ul>
  • <ul id="w48us"></ul>
  • <del id="w48us"></del>
    <ul id="w48us"></ul>
  • GRE考試技巧數學重要考點AP介紹

    時間:2024-07-15 16:21:28 GRE 我要投稿
    • 相關推薦

    GRE考試技巧關于數學重要考點AP介紹

      新GRE考試技巧:數學重要考點AP

    GRE考試技巧關于數學重要考點AP介紹

      新gre考試實施以來,不僅對寫作部分茫然不知所措,就連我們所擅長的數學也甚是擔憂,相信這其中的原因還是由于考生在新gre數學復習時沒有把基礎打牢。如果新版gre數學基本考點都沒有復習到,如何能拿到分數呢?所以說,想要新版gre數學考好,復習的時候一定要把基本概念和重要考點都弄扎實。 天針對新版gre數學復習,小編給大家整理的是關于平均數的相關內容,這些概念在考試中一定會考到的。希望考生能再接再厲,取得一個好成績,突破新版gre數學難的困境。

      AP

      Average of n numbers of arithmetic progression (AP) is the average of the smallest and the largest number of them. The average of m number can also be written as x + d(m-1)/2.

      Example:

      The average of all integers from 1 to 5 is (1+5)/2=3

      The average of all odd numbers from 3 to 3135 is (3+3135)/2=1569

      The average of all multiples of 7 from 14 to 126 is (14+126)/2=70

      remember:

      Make sure no number is missing in the middle.

      With more numbers, average of an ascending AP increases.

      With more numbers, average of a descending AP decreases.

      AP:numbers from sum

      given the sum s of m numbers of an AP with constant increment d, the numbers in the set can be calculated as follows:

      the first number x = s/m - d(m-1)/2,and the n-th number is s/m + d(2n-m-1)/2.

      Example:

      if the sum of 7 consecutive even numbers is 70, then the first number x = 70/7 - 2(7-1)/2 = 10 - 6 = 4.

      the last number (n=m=7)is 70/7+2(2*7-7-1)/2=10+6=16.the set is the even numbers from 4 to 16.

      Remember:

      given the first number x, it is easy to calculate other numbers using the formula for n-th number: x+(n-1)

      AP:numbers from average

      all m numbers of an AP can be calculated from the average. the first number x = c-d(m-1)/2, and the n-th number is c+d(2n-m-1)/2, where c is the average of m numbers.

      Example:

      if the average of 15 consecutive integers is 20, then the first number x=20-1*(15-1)/2=20-7=13 and the last number (n=m=15) is 20+1*(2*15-15-1)/2=20+7=27.

      if the average of 33 consecutive odd numbers is 67, then the first number x=67-2*(33-1)/2=67-32=35 and the last number (n=m=33) is 67+2*(2*33-33-1)/2=67+32=99.

      Remember:

      sum of the m numbers is c*m,where c is the average.

      由于美國數學基礎教育的難度增加導致數學考試越來越難,但新gre數學復習考點都是高中時候學到的知識點,考生不要過于緊張,把基本概念弄明白,再記住一些新版gre數學必備的詞匯,那么相信新版gre數學應該沒有問題。

    【GRE考試技巧數學重要考點AP介紹】相關文章:

    GRE數學考試技巧07-04

    GRE考試語法技巧介紹07-23

    精選新GRE數學的考試技巧匯總07-03

    GRE數學專項考試技巧推薦08-18

    gre考試閱讀高分技巧介紹07-21

    GRE考試技巧10-11

    GRE考試輔導-GRE同義表達的重要性和復習技巧09-30

    gre數學技巧08-07

    GRE數學考試技巧有哪些09-30

    GRE數學考試讀題的技巧08-21

    主站蜘蛛池模板: 一本大道久久a久久精品综合| 久久精品女人天堂AV麻| 国产精品福利在线观看免费不卡 | 正在播放国产精品每日更新| 四虎成人精品免费影院| 久久久一本精品99久久精品88| 久久精品无码一区二区三区免费 | 久久精品无码专区免费青青| 久久91这里精品国产2020| 中国精品videossex中国高清| 国产精品vⅰdeoxxxx国产| 中文字幕精品亚洲无线码二区 | 国产精品无码专区在线观看 | 国产女人精品视频国产灰线| 亚洲国产精品成人精品无码区| 久久久不卡国产精品一区二区| 国产精品无码久久综合网| 国产精品xxxx国产喷水亚洲国产精品无码久久一区 | 国产日韩高清三级精品人成| 欧美精品亚洲精品日韩| 国产久热精品无码激情| 精品无人区一区二区三区| 久久久无码人妻精品无码| 全球AV集中精品导航福利| 久久精品黄AA片一区二区三区| 亚洲AV无码久久精品成人| 亚洲一区爱区精品无码| 永久无码精品三区在线4| 中文字幕日韩精品有码视频| 亚洲午夜成人精品电影在线观看 | 精品国产品香蕉在线观看75| 99久久这里只有精品| 999在线视频精品免费播放观看| 国产综合精品一区二区三区| 国内精品久久久人妻中文字幕| 精品无码国产一区二区三区51安 | 日韩午夜高清福利片在线观看欧美亚洲精品suv| 精品人妻一区二区三区毛片| 久久精品国产福利国产琪琪| 欧美成人精品高清视频在线观看 | 99久久成人国产精品免费 |